Question

Consider a triangle ABC, right angle at B. The length of the base, AB= 4cm the length of perpendicular BC= 3cm. Find the value of sec A.

Answer 1

Answer:

sec A = 5/4

Explanation:

first find the length of the hypotenuse side as it p^2 + b^2 = h^2 . then as we know that sec A = h/b so it implies sec A = 5/4

Answer 2

Given :

Base of triangle (AB),

B = $4 \ cm$

Length of perpendicular (BC),

P = $3 \ cm$

To Find :

Value of Sec A = ?

Solution :

In a given right-angle ΔABC,

On applying Pythagoras theorem .i.e, "$H^2=P^2+B^2$" , we get

$H^2=3^2+4^2\\\\H^2=9+16\\\\H^2=25\\\\H=\sqrt{25}\\ \\H=5 \ cm$

As we know,

Sec A = $\frac{Hypotenuse}{Base}$ = $\frac{5}{4}$

then,

The value of Sec A is " $\frac{5}{4}$ ".