consider a two particle system with particles having masses m₁ and m₂ . if the first particle is pushed towards the centre of mass through a distance d , by what distance should particle be moved , so as to keep the centre of mass at the same position ? [AIEEE 2006]
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Answer:
No it is opposite side
Explanation:
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Explanation:- To keep the centre of mass at the same position velocity of centre of mass is 0 ,so
m₁ v₁ + m₂v₂ /m₁+ m₂ = 0
where ,v₁ and v₂ are the velocity of particles 1 and 2 , reapectevely .
⟹ m₁dr₁/dt + m₂dr₂/dt = 0
[ ∵ v₁ = dr₁/dt and v₂ = dr₂/dt ]
⟹ m₁dr₁ + m₂dr₂ = 0
dr₁ and dr₂ represenr the change in displacement of particles .
Let 2nd particles has been displaced by distance x
⟹ m₁d + m₂x = 0
or , x = -m₁d/m₂
or |x| = m₁d/m₂ Answer .
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