Question

Consider a uniform rod of mass m and length 2l with two particles of mass m each at its ends. Let AB be a line perpendicular to the length of rod and passig through its centre. Find the moment of inertial of the system about AB.

Answer 1

Thus the moment of inertia of the system about AB is I(AB)  =7 / 3 ml^2

Explanation:

Given data:

• Mass of rod = m
• length of rod = 2l

Solution:

To find moment of inertia of rod

IAB=Irod+Iboth particles  

=m(2l)^2 / 12 + 2(ml^2)

=7 / 3 ml^2

Thus the moment of inertia of the system about AB is I(AB)  =7 / 3 ml^2