Consider a vernier callipers in which each 1 cm on the man scale is divided in to 8 equal divisions and 9 man scale divisions are equal to 10 vernier scale division. Find the least count.
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Vernier Calipers:
1 cm is divided into 8 divisions, 1 main scale division is given as
8
1
cm
L.C. of Vernier is given as 1M.S.D−1V.S.D
Given 5 Vernier scale coincides with 4 main scale divisions:
5V.S.D=4M.S.D
L.C=1M.S.D−
5
4
M.S.D
L.C=1M.S.D−
5
4
M.S.D=
5
1
M.S.D=
40
1
cm
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