Question

Consider an ip address in a block is 110.23.120.14/20. Find the no of address

Answer 1

The network mask is 255.255.240.0.

a. The number of addresses in the network is 232 − 20 = 4096.

b. To find the first address, we apply the first short cut to bytes 1, 2, and 4 and the second

short cut to byte 3. The first address is 110.23.112.0/20.

Answer 2

Answer:

The network mask is 255.255.240.0.

a. The number of addresses in the network is 232 − 20 = 4096.

b. To find the first address, we apply the first short cut to bytes 1, 2, and 4 and the second short cut

to byte 3. The first address is 110.23.112.0/20.  

c. To find the last address, we apply the first short cut to bytes 1, 2, and 4 and the second short

cut to byte 3. The OR operation is applied to the complement of the mask. The last address is

110.23.127.255/20.