Question

Consider an unfair coin. The probability of getting heads is 0.6. If you toss this coin twice,
what is the probability that the first or the second toss is heads?
(A) 0.56 (B) 0.64 (C) 0.84 (D) 0.96

Answer 1

So the total possibilities for two tosses is {HH,TT,HT,TH} out of which we want {HH,HT,TH}

So probability is 0.6*0.6 + 0.6*0.4 + 0.4*0.6 = 0.84 (option C)

Answer 2

Answer:

0.84

Step-by-step explanation:

Given :  The probability of getting heads is 0.6.

To Find : what is the probability that the first or the second toss is heads?

Solution:

Sum of aal probabilities is 1

Since we are given The probability of getting heads is 0.6.

So probability of getting tail = 1-0.6=0.4

Since we are asked what is the probability that the first or the second toss is heads

total events  of tossing coins twice = {HH,HT,TH,TT}

Favorable events = {HH,HT,TH}

Thus the probability that the first or the second toss is heads = probability of(HH+HT+TH)=0.6*0.6+0.6*0.4+0.4*0.6 = 0.84

Thus Option C is correct 0.84