Question

Consider circle N with radius 30 cm and Theta equals StartFraction pi Over 6 End Fraction radians. Circle N is shown. Line segments L N and M N are radii with lengths of 30 centimeters. Angle L N M is theta. What is the approximate length of minor arc LM? Round to the nearest tenth of a centimeter.Consider circle N with radius 30 cm and Theta equals StartFraction pi Over 6 EndFraction radians.

Circle N is shown. Line segments L N and M N are radii with lengths of 30 centimeters. Angle L N M is theta.

What is the approximate length of minor arc LM? Round to the nearest tenth of a centimeter.

Answer 1

Length of Minor Arc = 15.7 cm if Radius = 30 cm and arc angle = π/6

Step-by-step explanation:

Circumference of Circle = 2πR

R = 30 cm

Circumference of Circle = 2π * 30  = 60 π  cm

Length of Minor Arc  = (θ / 360 ) * Circumference of Circle  if θ is in degrees

or

(θ / 2π ) * Circumference of Circle  if θ  is in Radians

=  (θ / 2π ) * 60 π

= 30 θ

θ = π/6

= 30 π/6

= 5 π

using π = 3.14

= 15.7 cm

Length of Minor Arc = 15.7 cm

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Answer 2

Answer:

15.7 centimeters

Step-by-step explanation:

Correct on edge