Question

Consider circle N with radius 30 cm and Theta equals StartFraction pi Over 6 EndFraction radians. Circle N is shown. Line segments L N and M N are radii with lengths of 30 centimeters. Angle L N M is theta. What is the approximate length of minor arc LM? Round to the nearest tenth of a centimeter.

Answer 1

length of minor arc LM = 15.7 cm  if arc angle = π/6 and radius = 30 cm

Step-by-step explanation:

LN = MN = Radius = 30 cm

∠ LNM = π/6    ( Arc Angle)

π/6 < π  ( Hence Minor Arc)

Length of Minor arc LM  =  (Arc Angle / 2π)  * 2πR

= ((π/6)/(2π) ) * 2πR

=  πR/6

= π * 30/6

= 5 π

using π = 3.14

= 5 * 3.14

= 15.7 cm

length of minor arc LM = 15.7 cm

Learn More

Consider circle N with radius 30 cm and Theta equals Start Fraction ...

https://brainly.in/question/13403789

The length of the arc AB is twice

brainly.in/question/11469201

The measure of an Arc of a circle is 90 deg

brainly.in/question/7568732

Answer 2

The approximate length of the minor arc LM will be 15.7 cm.

Step-by-step explanation:

The radius of the circle N is 30 cm.

So, the circumference of the circle is $2\pi r = 2 \times (\frac{22}{7}) \times 30 = 188.57$ cm.

Now, the angle that the arc LNM makes at the center of the circle N is $\frac{\pi }{6}$ .

Here, angle 2π is equivalent to circumference length 188.57 cm.

Hence, angle $\frac{\pi }{6}$ will be equivalent to the arc length of LNM = $\frac{188.57}{12} = 15.7$ cm.

Therefore, the approximate length of the minor arc LM will be 15.7 cm. (Answer)