consider f:R - R given by f(x) = 5x+2.
a.) show that f is one-one
b.) Is f invertible? Justify your answer.
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Solution :
Given function :
f : R → R , f(x) = 5x + 2
★ f(x) is one-one :
Let f(x1) = f(x2)
=> 5x1 + 2 = 5x2 + 2
=> 5x1 = 5x2
=> x1 = x2
→ Whenever f(x1) = f(x2) , then x1 = x2 .
Whenever f(x1) = f(x2) , then x1 = x2 . Thus , f(x) is one-one .
★ Whether f(x) is invertible :
→ If a function is one-one onto , then f(x) is invertible .
• Here , f(x) is one-one (shown above) .
Now ,
Let y = f(x)
=> y = 5x + 2
=> 5x = y - 2
=> x = (y - 2)/5
=> For x to be real , y can be any real number .
=> Range = R
=> Range = Co-domain
=> f(x) is onto .
→ Since f(x) is one-one onto ,
thus it is invertible function .
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