Question

Consider following reactions in equilibrium with equilibrium concentration 0.01
M of every species :
I : PCI, PCI, + CI,
II: H, +1, +2HI
III : N, + 3H, 2NH,
Extent of the reactions taking place is :
(1) I = II = III
(2) I <II < III
(3) III <II <I
(4) II <I< III​

Answer 1

Answer:

answer b

Explanation:

Here, molar concentration of each species at equilibrium=0.01M

I.PCl5⇔PCl3+Cl2

K=[PCl3][Cl2][PCl5]=0.01×0.010.01

=0.01=10−2

II.H2+I2⇔2HI

K=[HI]2[H2][I2]=(0.01)2(0.01)×(0.01)=1

III.N2+3H2⇔2NH3

K=[NH3]2[N2][H2]3=(0.01)2(0.01)×(0.01)3

=1(0.01)2=104

More K, more is the extent of reaction

∴ Order of extent of reaction is b

Answer 2

Answer:

st**id nonsense.... prostituter....bi**h