Question

"Consider the charges q,q and-q placed at vertices of an Equilateral triangle. What is the net force on each charges?"​

Answer 1

Answer:

Refer to the above attachment...

Answer 2

The force is zero.

EXPLANATION

Coulomb's Law state that

F = k.q1.q2 / r²

• F is the force.
• k is the Coulombic Constant.
• q1 and q2 are the charges.
• r is the distance.

F1 + F3 = Fres

In an equilateral triangle, θ = 60°

∴ Fres = F1 cosθ + F3 cosθ

• Since , F1 = F3 = F

Fres = 2F cosθ

= 2F × 0.5

= F

This is acting upwards. It is exactly balanced by

F2 acting downwards.

Since F2 = F then the net force on Q will be F − F =.0