Consider the circle S = x2 + y2 - 2x – 4y -4 = 0, the line L = 2x + 2y + 15 = 0 and the pointP (3, 4)
. Then,
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Given−PCisthetangentatapointCofthecirclewithdiameterABandcentreO.AB,extended,meetsPCatP&∠PCA=110o.Tofindout−∠CBA=Construction−WejoinOC.Solution−PCisthetangentatCandOCistheradiusfromOtoC.∴∠PCO=90oi.e∠OCA=110o−90o=20o.......(i)NowinΔOCAwehaveOC=OA(radiiofthesamecircle)∴ΔOCAisisosceles.⟹∠OCA=∠OACor∠BAC=20o...(ii)(fromi)Again∠ACBistheangleatthecircumferencesubtendedbythediameterABatC.So∠ACB=90o.....(iii)∠CBA=180
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