Question

Consider the circle x² + y2 + 2x - 4y = 0. The majority of the area contained in the circle lies in the quadrant.
plz answer fast​

Answer 1

Answer:

2nd quadrant

Step-by-step explanation:

Answer 2

Answer:

(x

2

+y

2

−2x−4y−4)+λ(x

2

+y

2

−10x−12y+40)=0

⟹x

2

+y

2

−2x(

1+λ

1+5λ

)−2y(

1+λ

2+6λ

)+

1+λ

40λ−4

=0

⟹16=(

1+λ

1+5λ

)

2

+(

1+λ

2+6λ

)

2

−

1+λ

40λ−4

⟹λ=

5

−1

,7

⟹(0,1),(

2

9

,

2

11

)