Consider the circuit given below when A, B and C are three identical light bulbs of constant resistance.
(a) List the bulbs in order of increasing brightness.
(b) If C burns out, what will be the brightness of A now compared with before?
(c) If B burns out instead, what will be the brightness of A and C compared with before?; Consider the circuit given below when A, B and C are three identical light bulbs of constant resistance.
(a) List the bulbs in order of increasing brightness.
(b) If C burns out, what will be the brightness of A now compared with before?
(c) If B burns out instead, what will be the brightness of A and C compared with before?
Answers
(a) Here A and B are connected in series so the brightness of the A and B will same while C are connected in parallel so the brightness of the bulb C is maximum.
(b) Their will be no effect on A and B.
(c) A and B are connected in series so if B burns than A also not glow but their will be no effect on C, as C is connected in parallel.
Explanation:
(a) The strength of both A and B is similar. Hence C is brighter as A and B , the same amount of current flows but the voltage is split into two parts. therefore the lamps A and B glow dimmer.
(b) As brightness of A will remain the same, because when bulb C burns out, the voltage distribution will have no effect.
(c) Bulb A is switched off because the current does not flow to it. if bulb B burns out because it is in a series circuit. C's brightness will remain the same as the same current flows through bulb C continuously.
You can get all the answers of Chapter 1 in the link below:
https://brainly.in/question/14961133
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