Question

consider the circuit show in fig 8.13.calculate the potential difference acrosee each resistor​

Answer 1

Answer:

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Answer 2

Explanation:

Here I

1

=

9

36−0

=4A

Also I

2

=

9

36−0

=4A

Also, 36−V

a

=I

1

×6=6I

1

=6×4=24V

∴V

a

=36−24=12V

36−Vb=3×4=12V

and V

b

=36−12=24V

ii. In loop ABCIHA

−6(I−I

1

)+3I

1

=0 or −6I+6I

1

+3I

1

=0

or 9I

1

=6I

∴I=

6

9

I

1

=

2

3

I

1

(i)

In loop CDEJIC,

−3(I−I

1

+1

2

)+6(I

1

−I

2

)=0

or −3I+3I

1

−3I

2

+6I

1

−6I

2

=0

or −3I+9I

1

−9I

2

=0 (ii)

In loop EFGHIJE,

36−3I

1

−6(I

1

−I

2

)=0

or 9I

1

−6I

2

=36 (iii)

After solving Eqs. (i), (ii), and (iii), we get

I

2

=3Afrombtoa.