Question

Consider the circuit shown in figure. The voltmeter on the left reads 10V and that on the right reads 8V.
Find (a) The current through the resistance R, (b) the value of R, and (c) the potential difference across
the battery.
Please give answer step by step
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Answer 1

Answer

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Answer 2

Given,

Voltmeter on left = 10V

Voltmeter on right = 8V

To find,

a) The current through the resistance R

b) the value of R

c) the potential difference across the battery.

Solution,

We start with the 3rd part as finding the potential difference will give us other values we need

c. Total resistance = Ri + 4

On Using Ohms law

V = IR

= I (Ri + 4)

= IRi+ I4

= 10 + 8

V = 18V = Potential difference across the battery

b. As of now,

IR = 10V

and I (4) = 8V

So,

(IR)/(I 4) = 10/8

R/4 = 10/8

R = 10 x 4/8

R = 5Ω

a. IR = 10V

and R = 5Ω

So

I = 10/5

= 2A

Thus,

The potential difference is 18V

Resistance is 5Ω

Current is 2A