Consider the circuit shown in the figure (32-E19a). Find (a) the current in the circuit (b) the potential drop across the 5 Ω resistor (c) the potential drop across the 10 Ω resistor (d) Answer the parts (a), (b) and (c) with reference to the figure (32-E19b).
figure 32-E19
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(a) In the above loop, when KVL is applied, we obtain:
10i + 6 + 5i + 12 = 0
⇒15i = -18
⇒I = -1815 = -65 = -1.2 A
The negative sign in this calculation shows that current is curving in the opposite direction to our expected direction.
(b) Across the 5 Ω resistor, the potential drops = 5i = -6 V
(c) Across the 10 Ω resistor, the drop in potential = 10i = 10 x (-1.2) = 12 V
(d) In above loop, when KVL is applied, we obtain:
10i + 5i + 6 + 12 = 0
⇒I = -1.2 A
Across the 5Ω register, the potential drop = -6 V
Across the 10Ω register, the potential drop = -12 V
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