Question

Find the current measured by the ammeter in the circuit shown in the figure (32-E18).
figure 32-E18

Answer 1

Answer:

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Explanation:

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Answer 2

Explanation:

• We can observe from the circuit’s symmetry that at point C, the potential will be identical to the point F’s potential.
• This shows that there can be no current flow in this branch. Therefore, the circuit’s art can be detached.
• Likewise, at point B, the potential will be identical to the point G’s potential. Therefore, the circuit’s arm can also be detached.
• The basic circuit illustration is shown below.
• The circuit’s effective resistance,

Reff = 3030 x 30 + 30 = 15 Ω

The current via the circuit, i = 0.4 A.

So, the reading of the ammeter will be 0.4 A.