Consider the combustion reaction of acetylene (c2h2) : 2c2h2 + 5o2 4co2 + 2h2o use the periodic table to determine how many grams of oxygen would be required to react completely with 859.0 g c2h2?
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25g * (1 mole/74.1g) = .337 moles of Ca(OH)2
Now, the mole ratio tells us that we need DOUBLE that of HCl. Ergo,
.337 mol Ca(OH)2 * (2 mol HCl/1 mol Ca(OH)2) = .675 moles of HCl.
Now using the molarity of the HCl and the number of moles of HCl, we can determine the number of liters.
.675 mol * (1 L/.150 mol) = 4.50 L HCl
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Answer:
2,640
Explanation:
i just did it
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