Physics, asked by ranjanmah2996, 1 year ago

Consider the conductor to be a coil of turns 60 and the flux density to be 13.5 units, current 0.12a and area 16units. The torque will be

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Answered by Anonymous
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Answer:-

For a single turn or loop, the torque will be BIA. For N turns, the torque will be T = NBIA, where N = 60, B = 13.5, I = 0.12 and A = 16. Thus T = 60 x 13.5 x 0.12 x 16 = 1555.2 units.
Answered by Anonymous
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