Physics, asked by StarTbia, 1 year ago

Consider the decay of a free neutron at rest : n → p + e⁻Show that the two-body decay of this type must necessarily give an electron of fixed energy and therefore cannot account for the observed continuous energy distribution in the β-decay of a neutron or a nucleus (As shown in figure).

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Answered by gadakhsanket
5
Hey mate,

● Step by step Explaination-
Here, decay process of free neutron at rest is given by
n → p + e–

From Einstein’s theory of relativity,
E = Δmc^2
Where, Δm and c are constants.
Δm = Mass defect
Δm = n – (p + e-)
c = Speed of light

Therefore, the given two-body decay is unable to explain the continuous energy distribution in the β-decay of a neutron or a nucleus.

Hope this is useful...
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