Question

Consider the figure,ABCD is a rhombus. Its diagonals meet at O. if diagonal AC=24cm and AB=13cm, find the distance OD

Answer 1

Answer:

5cm

Explanation:

In right triangle DOC

By using pythagorus theorem

DCsq. = ODsq.+OCsq.

ODsq. = DCsq. – OCsq.

= 13*13 – 12*12

= 196 – 144

ODsq. = 25

Taking square root on both side

OD = 5cm

Answer 2

Answer:

diagonals of rhombus are perpendicular bisector of each other.

triangle OADis right angle triangle.

by pythagoras theorem

AB2 = OA2 + OB2

169 = 144 + OB2

OB2 = 25

OB = 5

but OB = OD

Therefore, OD = 5