Question

In figure 13.42 C is the centre of the circle. CB bisects the angle DBE , CD is perpendicular to PQ and CE is perpendicular to RS. prove that PQ = RS.
explain in detail with using the theorems and all....​

Answer 1

Answer:

Step-by-step explanation:

To prove: PQ=RS

Proof:In triangles CBE and CBD

Angle CDB= Angle CEB{ 90°}

CB=CB{common side}

Angle CBE=Angle CBD{ CB is the angle bisector of angle dbe}

∆cbe is congruent to ∆ CBD{ ASA axiom}

CE=CD{cpct}

Chords of a circle that are equidistant from the centre are equal

Answer 2

Answer:

the solution is through attachement ...

from .sahil

khan

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