Consider the following arithmetic operations in C: int X-20; int Y-20; int Z-2*(X Y) which assembly code(0x86) does not evaluate value for Z correctly? mov eax.X b) mov ebx. Y add eax ebx mov el.4 mov ebx.Y a) add eax.ebx mov cl.2 imul cl mov Z eax imul cl shr eax. 1 mov Z.eax d) mov eax.X mov ebx.Y add eax.ebx shl eax, I mov Z,eax mov eax X c) mov ebx,Y shl eax.2 shl eax.2 add eax.ebx
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Answered by
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Answer:
Here Question is the option which doesn't evaluate Z correctly then the answer is A
But, if you see which option doesn't evaluate Z then the Answer is C
c) Operation
It calculates the value . But, never stores the value in Z.
a) Operation
It evaluates the value of Z in-correctly.As, it never considers the value of X and without any check it adds the value of ebx i.e Y to eax .
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Explanation:
consider the following arithmetic operation in c
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