Question

Consider the following array declarations. Find the number of elements in
each array and total number. of bytes required by each array.
(a) int x [ 5 ] [ 10 ];
(b) long y [ 5 ] [ 10 ];

Answer 1

C | Arrays | Question 7

Consider the following declaration of a ‘two-dimensional array in C:

char a[100][100];

Assuming that the main memory is byte-addressable and that the array is stored starting from memory address 0, the address of a[40][50] is (GATE CS 2002)

(A) 4040

(B) 4050

(C) 5040

(D) 5050

Answer: (B)

Explanation:

Address of a[40][50] = Base address + 40*100*element_size + 50*element_size

= 0 + 4000*1 + 50*1

= 4050

Based on row major or column major

if row major then the result will be 4050

if column major then

Address of a[40][50] = Base address + 50*100*element_size + 40*element_size

= 0 + 5000*1 + 40*1

= 5040

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