Consider the following distribution of daily wages of 50 worker of a factory. Daily wages (in Rs) 100 − 120 120 − 140 140 −1 60 160 − 180 180 − 200 Number of workers 12 14 8 6 10 Find the mean daily wages of the workers of the factory by using an appropriate method.
Answers
Answer:
The mean daily wage of the workers is ₹ 145.20 .
Step-by-step explanation:
MEAN (Step deviation method) = A + h ×(Σfiui /Σfi) , where ui = (xi - A )/h
FREQUENCY DISTRIBUTION TABLE IS IN THE ATTACHMENT
From the table : Σfiui = -12 , Σfi = 50
Let the assumed mean, A = 150, h = 20
MEAN = A + h ×(Σfiui /Σfi)
MEAN = 150 + 20(-12/50)
= 150 - 24/5
= 150 - 4.8
= 145.2
Hence, the mean daily wage of the workers is ₹ 145.20 .
STEP DEVIATION METHOD:
Step deviation method is used in the cases where the deviation from the assumed mean 'A' are multiples of a common number. If the values of ‘di’ for each class is a multiple of ‘h’ the calculation become simpler by taking ui= di/h = (xi - A )/h
Here, h is the class size of each class interval.
★★ Find the class marks of class interval. These class marks would serve as the representative of whole class and are represented by xi.
★★ Class marks (xi) = ( lower limit + upper limit) /2
★★ We may take Assumed mean 'A’ to be that xi which lies in the middle of x1 ,x2 …..xn
MEAN = A + h ×(Σfiui /Σfi) , where ui = (xi - A )/h
HOPE THIS ANSWER WILL HELP YOU….
Direct Mean Method:
Hope you like the simplest way of calculating mean.