Question

Consider the following four electrodes:
P = Cu²⁺ (0.0001 M)/Cu(s)
Q = Cu²⁺ (0.1 M)/Cu(s)
R = Cu²⁺ (0.01 M)/Cu(s)
S = Cu²⁺ (0.001 M)/Cu(s)
If the standard reduction potential of Cu²⁺/Cu is +0.34 V, the reduction potentials in volts of the above electrodes follow the order.
(a) P > S > R > Q
(b) S > R > Q > P
(c) R > S > Q > P
(d) Q > R > S > P

Answer 1

$<b>$
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$\mathbb{NICE...QUESTION}$

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→ [B]

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Answer 2

Here is your answer ⤵⤵⤵

(b)

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