Question

⏺️⏺️
Consider the following isomerisms:
(1) Ionization (II) Hydrate
(III) Coordinate (IV) Lignd
Which of the above isomerism
exhibited by
[Cr(NH3)2(H20)4]C12?
(1) I and II
(2) Only II
(3) II and III
(4) III and IV

Explain your answer..⏺️⏺️​

Answer 1

Answer :

[Cr(NH₃)₂(H₂O)₄]Cl₂ exhibits hydrate isomerism.

• $\sf{[Cr(NH_3)_2(H_2O)_4]Cl_2}$
• $\sf{[Cr(NH_3)_2(H_2O)_3Cl]Cl\:H_2O}$

◈ Hydrate isomerism :

Complexes that differ in number of water molecules present as ligands (inside coordinate sphere) and as free molecules (outside the coordinate sphere)$.$

• $\sf{[Cr(H_2O)_6]Cl_3}$
• $\sf{[Cr(H_3O)_5Cl]Cl_2\:H_2O}$

◈ Ionisation isomerism :

Complexes that give different ions in solution.

• $\sf{[Co(NH_3)_5Br]SO_4}$
• $\sf{[Co(NH_3)_5SO_4]Br}$

◈ Coordination isomerism :

Occurs when both positive and negative ions are complex ions and two isomers differs in ligands distribution in two complex ions.

• $\sf{[Co(NH_3)_6][Cr(CN)_6]}$
• $\sf{[Cr(NH_3)_6][Co(CN)_6]}$

◈ Linkage isomerism :

Complexes that differ in the atom of a ligands directly bonded to the metal atom, shown by complexes containing ambidentate ligands.

• $\sf{[Co(NH_3)_5(NO_3)]Cl_2}$
• $\sf{[Co(NH_3)_5(ONO)]Cl_2}$