Question

Consider the following processes :
∆H (kJ/mol)
1/2 A → B +150
3B → 2C + D –125
E + A → 2D +350
For B + D → E + 2C, ∆H will be :
(a) 525 kJ/mol (b) – 175 kJ/mol
(c) – 325 kJ/mol (d) 325 kJ/mol

Answer 1

Answer:

(b)-175kJ/mol

Explanation:

2×1/2A = 2B; 300KJ/mol

3B = 2C+D; -125KJ/mol

2D = E + A; -350KJ/mol

_______________________________

B + D = E + 2C;. ∆H = ( 300 - 125 - 350 )

∆H = -175KJ/mol