Question

In conversion of lime-stone to lime,
CaCO₃(s) → CaO(s) +CO₂(g) the values of ∆H° and ∆S°
are + 179.1 kJ mol⁻¹ and 160.2 J/K respectively at 298 K and
1 bar. Assuming that ∆H° and ∆S° do not change with
temperature, temperature above which conversion of
limestone to lime will be spontaneous is
(a) 1118 K (b) 1008 K
(c) 1200 K (d) 845 K.

Answer 1

The temperature above which conversion of  limestone to lime will be spontaneous is   T = 1118 K

Option (A) is correct.

Explanation:

We know that:

ΔG ∘ =ΔH∘  − TΔS ∘

 For spontaneous process, ΔG < O

ΔH − TΔS < O

ΔH∘ /  ΔS∘ < T

ΔH∘  = 179.1 KJ mol −1  andΔS  ∘  =160.2 J/K

T >    179.1×1000   / 160.2 K mol−1

T = 1117.91117.9

 T = 1118 K

Thus the temperature above which conversion of  limestone to lime will be spontaneous is   T = 1118 K

Also learn more

What is spontaneous process? Give examples.

https://brainly.in/question/6091314

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