Consider the following radioactive decay of 238 U 2380—+ "He- In a closed vessel of 11.2 ml 5.95 g of uranium is taken , then the total pressure at the end of 36 years at 0°C is (ty2 of 238U is 12 years) (1) 1 atm (2) 20 atm (3) 35 atm (4) 43.7 atm
Answers
Answered by
0
Answer:
43.7 atm
Explanation:
Consider the following radioactive decay of 238 U 2380—+ "He- In a closed vessel of 11.2 ml 5.95 g of uranium is taken , then the total pressure at the end of 36 years at 0°C is 43.7 atm
Answered by
0
Explanation:
14
N+
2
4
Hc→
8
17
O+
1
1
H
4
9
Be+
2
4
He→
6
12
C+
0
1
n
4
9
Be(p,α)
3
6
Li
15
30
P→
14
30
Si+
+1
0
e
1
3
H→
2
3
He+
−1
0
e
20
43
Ca(α,....)→
21
46
Sc+p(proton)
In these equations, the sum of the atomic numbers on LHS is equal to the sum of the atomic numbers on RHS.
Similarly, the sum of the mass numbers on LHS is equal to the sum of the mass numbers on RHS
Similar questions