Consider the following reaction,
PBr₃ alc.KOH (i) H₂SO₄ room temperature
Ethanol ➝ X ➝ Y ➝ Z
(ii)H₂O,heat
the product Z is:
(a) CH₃CH₂-O-CH₂-CH₃
(b) CH₃-CH₂-O-SO₃H
(c) CH₃CH₂OH
(d) CH₂=CH₂
Answers
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2
Answer:
c
Explanation:
C2H5OH----PBr3--- C2H5Br----KOH-----CH2=CH2---H2SO4----- CH3CH2HSO4-------H2O------CH3CH2OH
Answered by
0
pBr3 will give SN2 reaction
C2H5OH ⟶C2H5BR
Alc.koh will give elimination reaction and forms the double bond
C2H5Br⟶C2H4
H2SO4,H30 will give electrophilic addition reaction
C2H4⟶C2H5OH
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