Question

Δ DEF काढा. DE = EF = 6 सेमी ∠F = 45°. या त्रिकोणाचे परिवर्तुळ काढा.

Answer 1

Given :

In ∆DEF , DE = EF= 6

<F = 45°

Proof :

∆DEF , DE = EF = 6

<D = <F = 45°

[ Angles opposite to equal

sides are equal ]

Now ,

<E + <D + <F = 180°

=> <E + 45° + 45° = 180°

=> <E = 180° - 90°

= 90°

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