Question

Consider the following relations for emf of a electrochemical
cell:
(i) emf of cell = (Oxidation potential of anode) –
(Reduction potential of cathode)
(ii) emf of cell = (Oxidation potential of anode) + (Reduction
potential of cathode)
(iii) emf of cell = (Reduction potential of anode) + (Reduction
potential of cathode)
(iv) emf of cell = (Oxidation potential of anode) – (Oxidation
potential of cathode)
Which of the above relations are correct?
(a) (ii) and (iv) (b) (iii) and (i)
(c) (i) and (ii) (d) (iii) and (iv)

Answer 1

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❤.option A is correct

Answer 2

Relations for emf of a electrochemical cell is :

• We know that in electrochemical cell oxidation occurs at anode and reduction at cathode.

• Hence option (iii) and (iv) is eliminated.

• Ecell = (Oxidation potential of anode) – (Reduction potential of cathode)

•And Ecell = (ii) emf of cell = (Oxidation potential of anode) + (Reduction potential of cathode)

• Therefore, correct option is (c) (i) and (ii)