Question

Consider the function f:R − 0 → R, defined by f(x) = x + 1/x , x ∈ R, x ≠ 0. Then f is:
1. Injective.
2. Bijective.
3. Surjective
4. None of the above.

Please no BS answers. It is needed urgently.

Answer 1

Answer:

4. None of the above

Step-by-step explanation:

It is not injective as f(1/2) = f(2)

It is not surjective because (-2, 2) is not in range of f. For positive x, it is never below 2, and for negative x, it is never above -2.