Consider the line L with equation y + 2x = 3. The line L1
is parallel to L and passes through the
point (6, –4).
(a) Find the gradient of L1
.
(b) Find the equation of L1
in the form y = mx + b.
(c) Find the x-coordinate of the point where line L1 crosses the x-axis.
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Answer:
Hello,
\begin{gathered}a)L:y=-2x+3\ slope\ or\ gradient=-2\\ b) L_1: y+4=-2(x-6)==\ \textgreater \ y=-2x+8\\ c) y=0=-2x+8==\textgreater\ x=4\end{gathered}
a)L:y=−2x+3 slope or gradient=−2
b)L
1
:y+4=−2(x−6)== \textgreater y=−2x+8
c)y=0=−2x+8==\textgreater x=4
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