consider the sequence 5,9,13,17 a)2017 is a term of the sequence b)if the difference of any two terms in 2020
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Step-by-step explanation:
( (a) )
since,
5,9,13,17 are in AP
a=5 d=9-5=4
For checking 2017 is a term of an AP or not,,,
let 2017 is a term of an AP
so if it is an term of an AP then it should have a place in an AP
let n'th term of an AP is 2017
then
An = a+(n-1) d
2017=5+(n-1)4
2017-5=4n-4
2012+4=4n
2016=4n
2016/4=n
504=n
yes 2017 is a term of an AP....
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