Question

consider the two computers A and B with clock cycle times 100ps and 150 ps respectively for some program.the number of cycles per instruction (CPI) for A and B are 2.0 and 1.0 respectively for the same program.which computer is faster and how much?

Answer 1

Answer:

Computer B is Faster

Explanation:

consider the two computers A and B with clock cycle times 100ps and 150 ps respectively for some program.the number of cycles per instruction (CPI) for A and B are 2.0 and 1.0 respectively for the same program.which computer is faster and how much?

Computer A clock cycle times 100ps

Number of cycle per instruction = 2

Time Required Per instruction = 100 * 2 = 200 ps

Computer B clock cycle times 150ps

Number of cycle per instruction = 1

Time Required Per instruction = 150 * 1 = 150 ps

Computer B requires less time than Computer A per instruction

Computer B is Faster

Computer B is Faster 200 - 150 = 50ps Faster Per instruction

Answer 2

Answer:

b

Explain

this answer is correct