Consider the two molecules :
H H H
| \ ⁄
H₃C C H₃C C CH₃
\ ⁄ \\ \ ⁄ \ ⁄
(I) C C - CH₃ (II) C C
ǀǀ | ǀǀ | \
O O O O H
⁄ ⁄
H H
Which of the following statements about them is true ?
(a) II is capable of forming intramolecular hydrogen
bonding whereas I is not
(b) Both are capable of forming equally stable
intramolecular hydrogen bonding
(c) I is likely to form more stable intramolecular hydrogen
bonding than II
(d) Both of them cannot form intramolecular hydrogen
bonding
Answers
Answered by
0
I is likely to form more stable intramolecular hydrogen
bonding than II.
Explanation:
- Hydrogen bond is an imaginary bond formed between an atom of Oxygen, Fluorine or nitrogen with a hydrogen atom attached with another atom of hydrogen, nitrogen or fluorine.
- Hydrogen bonds formed within a molecule is called intramolecular hydrogen bonding.
- In case of compound 2,the carbon at the top is having so3 hybridization while in compound 1, the carbon at the top is having sp2 hybridization.
- So the compound 2 is not planar while compound 1 is planar.
- So the compound 1 will have less distance between the bonding oxygen and hydrogen which will facilitate the hydrogen bonding.
- In case of compound 2, this isn't the case.
For more information about hydrogen bonding,
https://brainly.in/question/8041678
Which hydrogen bonding is more stronger among oxygen-chlorine and oxygen-hydrogen?
https://brainly.in/question/8046309
Name the two conditions which must be satisfied for hydrogen bonding to take place in a molecule.
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