Question

Consider this reaction and its rate law. 3A + 2B –> products

Answer 1

the following reaction is governed by law of active mass.
kf is proportional to (A)^3 × (B)^2.

Answer 2

Answer: $Rate=k[A]^3[B]^2$

$3A+2B\rightarrow products$

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For elementary reactions taking place in one step, the order is the same as the stochiometric coefficients.

$Rate=k[A]^x[B]^y$

k= rate constant

x = order with respect to A  = 3

y = order with respect to B = 2

$Rate=k[A]^3[B]^2$

Total order = x+y = 3+2 = 5