Consider those numbers between 100 and 1000 such that when each number is divided by 6, 7 and 11 it leaves 5 as remainder in each case. What is the sum of the numbers?
Answers
Answered by
9
sum = 1000 ÷ 100 = 10
so divided 6 by 10 = 1
♥Hope it helps♥
Answered by
0
Answer:
462 is correct ans of this question
Similar questions