Question

consider triangle of sides 4cm 5cm and 6cm and then a triangle similar to whose sides are 2 by 3 of the corresponding sides of the first triangle

Answer 1

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Answer 2

Solution: Making the triangle.

.Draw a line segment AB = 4 cm

.Draw an arc at 5 cm from point A.

.Draw an arc at 6 cm from point B so that it intersects the previous arc.

.Joint the point of intersection from A and B.

.This gives the required triangle ABC.


Dividing the base in 2 : 3 ratio:

.Draw a ray AX at an acute angle from AB.

.Plot three points on AX so that; AA1 = A1A2 = A2A3

.Join A3 to B.

.Draw a line from point A2 so that this line is parallel to A3B and intersects AB at point B’.

.Draw a line from point B’ parallel to BC so that this line intersects AC at point C’.

Triangle AB’C’ is the required triangle.