Question

consider two forces f1 and f2 of magnitude 17N and 9N acting on a particle as shown in the diagram . What is the magnitude and direction of the resultant force

Answer 1

Answer:

I dont no

next time I may tell

Answer 2

Answer: 17.77 N

Explanation: This is a resolving force Question, which means you are gonna resolve both F1 and F2 into two perpendicular components on the X-axis and the Y-axis

To resolve the force into a component on the X-axis we need to divide it by the force's original value, to do that we need to use the angle and find the X-axis using Cos (we use cosine because it will give us the component of the adjacent line which is X in this case and the hypotenuse which is the force itself, you could use sin if the x and the force were opposite and hypotenuse respectively)

To resolve the force into a component on the Y-axis we need to divide it by the force's original value, to do that we need to use the angle and find the Y-axis using Sin (we use sine because it will give us the component of the opposite line which is Y in this case and the hypotenuse which is the force itself, you could use cos if the y and the force were adjacent and hypotenuse respectively)

F1

Fx1 = Cos(27)*17 = +15.147N

Fy1 = Sin(27)*17  = +7.7N

(The resultants here are positive because the force is resolved on the positive axis of both X and Y

F2

Fx2 = Cos(54)*9 = -5.29N

(The resultant here is negative because it's resolved on the negative X-axis)

Fy2 = Sin(54)*9 = +7.28

The resultant force

Fx = Fx1 + Fx2 = +15.147-5.29 = 9.857N

Fy = Fy1 + Fy2 = +7.7+7.28 = 14.98

Fnet = √(Fx)^2+(Fy)^2 = √(9.857)^2+(14.98)^2 = 17.778 N