Question

Consider two numbers, whose HCF and LCM are 33 and 264 respectively. The first number is completely divisible by 2 and gives quotient 33. What is the other number?
(a) 66 (b) 132 (c) 58 (d) 73​​

Answer 1

Answer:

Let the first number be a and the other number is b.

Therefore, LCM (a,b) = 264 and HCF (a,b) = 33

Since, the first number is completely divided by 2, the quotient is 33, a = 2 × 33 = 66

As we know a × b = LCM(a,b) × HCF(a,b)

Then b = [LCM(a,b) × HCF(a,b)] ÷ a

b = (264 × 33) ÷ 66 = 132

therefore 132 is the ans i.e b

HOPE IT HELPS YOU

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Answer 2

(a) 66

assume that the two numbers are x and y.

We are given that when the first number is completely divided by 2, the quotient is 33. Turning this into a mathematical statement we get:

x=2×33

⟹x=66

hence, the other number is 66