consider two right angles triangle with sides a, b, c and A, B, C, respectively. if a/A=b/B, then show that c/C=a/A. Does the result hold when the triangles are not right angle? justify your answer
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Step-by-step explanation:
consider two right angles triangle with sides a, b, c and A, B, C, respectively. if a/A=b/B, then show that c/C=a/A
as it is an right angle triangle so
c² = a² + b²
C² = A² + B²
a/A=b/B = K
=> a = AK
b = BK
c² = (AK)² + (BK)²
=> c² = K²(A² + B²)
=> c² = K²(C²)
Taking square rot both sides
c = KC
=>c/C = k
hence
a/A=b/B = c/C
Triangles are similar when Corresponding sides are in proportion or corresponding angles are equal
Result will hold true even if triangle is not right angle triangle but
corresponding angle must be equal in that case
if corresponding angles are not equal then result will not hold true
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