Question

considered A body moving with velocity 9m/s . if is subjected to acceleration-2m/s².calculate the distance travelled by its body in 5th second.​

Answer 1

Answer:

u = 9m/s

a = -2m/s^2

t = 5s

s = ?

s = ut + 1/2at^2

s = 9m/s * 5s + 1/2 * -2m/s^2 * ( 5s )^2

s = 45m + ( -1m/s^2 ) * 25s^2

s = 45m - 25m

s = 20m

hope it helps

Answer 2

Answer:

18m

Step-by-step explanation:

using the formula S=ut+1/2at^2, where S is distance travelled in t seconds, initial velocity u, acceleration a for 4 seconds(=S1) and 5 seconds (=S2). Hence, the distance travelled in 5th second will be S2-S1(S2 and S1 are only the names of the variables)

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