Physics, asked by priyanshu3854, 1 year ago

constant force act on the object of mass 6 kg for a duration of 3 second its increase the object velocity from 3 metre per second to 9 metre per second. find the magnitude of the applied force

Answers

Answered by ambrishpratapsingh8

the average acceleration will be 2 metre per second square show the net force applied on the body will be 12 Newton

priyanshu3854: i need solution not answer

ambrishpratapsingh8: I have given the solution not the answer I have defined the full procedure how to solve this question but if you don't know the basic of Physics then I think you need to revise your concepts again

Answered by Anonymous

Hey!!!!

Given:

$m = 6kg$
$t = 3sec$
$u = 3 \frac{m}{s}$
$v = 9 \frac{m}{s}$

Since,
$f = ma$
$f = m( \frac{v - u}{t} )$
Since
$a = \frac{v - u}{t}$
Therefore by putting the given values...

$f = 6( \frac{9 - 3}{3} )$
$= 6 ( \frac{6}{3})$
$= 6(2)$
$= 12$

Therefore, the force applied is 12 N.

#BE BRAINLY

priyanshu3854: thax

priyanshu3854: hello

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