Question

Constract a parallelogram ABCD. Given AB=10cm BC=12cm angleB= 80° measure BD

Answer 1

Answer:

Area of Parallelogram ABCD=2×ar△ABC

ar△ABC=

s(s−a)(s−b)(s−c)

s=

2

a+b+c

=

2

16+10+12

=19cm

ar△ABC=

19(19−16)×(19−10)(19−12)

=

169×3×9×7

=59.9cm

2

∴ area of parallelogram ABCD=2×59.9=119.8cm

2

Now, area of parallelogram ABCD=base X height

119.8=10×h⇒h=11.98cm

∴ Distance between the shortest sides is 11.98cm