Question

Construct 150 degrees

Answer 1

Let us make use of the fact (as mentioned by Satyadev and Vivek ) that 150∘=180∘−30∘=180∘−(12×60∘).

180∘ is easy — just a line segment.

60∘ is also easy — the angle in an equilateral triangle. So, the construction is simple.

Bisecting an angle is easy.

So, here goes …

Take a line segment, say, AB .

Choose a point C on it.

With center C , and radius BC , draw an arc.

With center B and radius BC , cut the previous arc at say D . ( ∠DCB=60∘ because we just made CD=BC=BD .)

With center D , and radius BC draw an arc.

With center B and radius BC , cut this arc at, say, E . Then EC is the bisector of ∠BCD , and hence ∠BCE =30∘ .

Then, ∠ACE=180∘−∠BCE=150∘.

hope you understand

Answer 2

Step-by-step explanation:

Refer to the attachment ...

mark an arc from 120 degree angle and another from 180 degree ,where both intersect mark a point and extend the line to the centre .

here u get your 150 degree angle