construct √150° using compass
Answers
Answered by
2
Answer:
.Take a line segment, say, AB.
Choose a point C on it.
With center C, and radius BC, draw an arc.
With center B and radius BC, cut the previous arc at say DD. (∠DCB=60∘∠DCB=60∘because we just made CD=BC=BD .)
With center D, and radius BC draw an arc.
With center B and radius BC, cut this arc at, say, EE. Then EC is the bisector of ∠BCD, and hence ∠BCE=30∘
.Then, ∠ACE=180∘−∠BCE=150∘.
Similar questions